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CCS/TM4C123GH6PM: TM4C123GH6PM

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Part Number:TM4C123GH6PM

Tool/software: Code Composer Studio

I'm trying to wrap my brain around why the open drain has a voltage across it.  I'm using GPIO PA7.  In code composer I've got the lines:

SysCtlPeripheralEnable(SYSCTL_PERIPH_GPIOA);
GPIOPinTypeGPIOOutputOD(GPIO_PORTA_BASE, GPIO_PIN_7);

I'm trying to drive an optoisolator (see circuit in image).  When the GPIO goes high it pulls the drain to ~1.3 to 1.5 V.  Should the voltage between the D to S voltage be that much?


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