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LM25011: About current limit.

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Part Number:LM25011

Hi team.

We want to calculation the maximum power dissipation when in current limit.

According to data sheet(p.18), 

P(RS) = ( the maximum thresholds + Ripple current / 4 ) ^2  × Rs

However I think Ripple current is half the ripple amplitude.

Why are you divided Ripple current by 4?

Sincerely.

Kengo.


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